# Python program to sort tuples by frequency of their absolute difference

Given list of dual tuples, the task here is to write a python program that can sort them by frequency of their elements’ absolute difference.

Input: [(1, 6), (11, 3), (9, 1), (6, 11), (2, 10), (5, 7)]Attention geek! Strengthen your foundations with the

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Output :[(5, 7), (1, 6), (6, 11), (11, 3), (9, 1), (2, 10)]

Explanation :7 – 5 = 2 occurs only 1 time. 5 occurs twice [( 6 – 1), (11 – 6)] and 8 occurs 3 times as difference.

Input :[(1, 6), (6, 11), (5, 7)]

Output :[(5, 7), (1, 6), (6, 11)]

Explanation :7 – 5 = 2 occurs only 1 time. 5 occurs twice [( 6 – 1), (11 – 6)].

**Method : ***Using **sorted()**, **abs()**, **count()** and **list comprehension*

In this, we perform task of computing each absolute difference using abs() and list comprehension. Then, sorted() and count() are used to sort tuples based on computed results of absolute difference.

**Example:**

## Python3

`# initializing list` `test_list ` `=` `[(` `1` `, ` `6` `), (` `11` `, ` `3` `), (` `9` `, ` `1` `), (` `6` `, ` `11` `), (` `2` `, ` `10` `), (` `5` `, ` `7` `)]` ` ` `# printing original list` `print` `(` `"The original list is : "` `+` `str` `(test_list))` ` ` `# getting differences pairs` `diff_list ` `=` `[` `abs` `(x ` `-` `y) ` `for` `x, y ` `in` `test_list]` ` ` `# sorting list by computed differences` `res ` `=` `sorted` `(test_list, key ` `=` `lambda` `sub: diff_list.count(` `abs` `(sub[` `0` `] ` `-` `sub[` `1` `])))` ` ` `# printing result` `print` `(` `"Sorted Tuples : "` `+` `str` `(res))` |

**Output:**

The original list is : [(1, 6), (11, 3), (9, 1), (6, 11), (2, 10), (5, 7)]

Sorted Tuples : [(5, 7), (1, 6), (6, 11), (11, 3), (9, 1), (2, 10)]